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9.5x^2+45x+18=0
a = 9.5; b = 45; c = +18;
Δ = b2-4ac
Δ = 452-4·9.5·18
Δ = 1341
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1341}=\sqrt{9*149}=\sqrt{9}*\sqrt{149}=3\sqrt{149}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-3\sqrt{149}}{2*9.5}=\frac{-45-3\sqrt{149}}{19} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+3\sqrt{149}}{2*9.5}=\frac{-45+3\sqrt{149}}{19} $
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